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12p^2-7=p
We move all terms to the left:
12p^2-7-(p)=0
We add all the numbers together, and all the variables
12p^2-1p-7=0
a = 12; b = -1; c = -7;
Δ = b2-4ac
Δ = -12-4·12·(-7)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{337}}{2*12}=\frac{1-\sqrt{337}}{24} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{337}}{2*12}=\frac{1+\sqrt{337}}{24} $
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